Section 8.2 Part 2: Analysis

While this comment could have been absorbed into the previous comment on this section, it is important to note that Hungerford specifies that Na=aN does not imply that na=an for every n\in N when dealing with groups and normal groups. 

I find it interesting that the statement a^-1 Na\subseteq N for every a\in G , where aNa^-1 ={ana^-1\mid n\in N and the statement a^-1 Na=N for every a\in G are equivalent.

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